Question

(5) \\(5 - \frac{2}{3} + \frac{1}{2}\\)
\\(= 4\frac{\square}{6} - \frac{4}{6} + \frac{3}{6}\\)
\\(=\\)

(6) \\(6 - \frac{1}{2} + \frac{1}{4}\\)
\\(=\\)

(7) \\(5 - 4\frac{3}{4} + \frac{1}{4}\\)
\\(=\\)

(8) \\(3 - \frac{1}{5} - \frac{7}{10}\\)
\\(=\\)

Explanation:

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"Fraction Subtraction",
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"Common Denominator",
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<reasoning>

Solve Question 5

\[

$$\begin{aligned} 5 - \frac{2}{3} + \frac{1}{2} &= 4\frac{6}{6} - \frac{4}{6} + \frac{3}{6} \\ &= 4\frac{6 - 4 + 3}{6} \\ &= 4\frac{5}{6} \end{aligned}$$

\]
The missing value in the box is \(6\).

Solve Question 6

\[

$$\begin{aligned} 6 - \frac{1}{2} + \frac{1}{4} &= 5\frac{4}{4} - \frac{2}{4} + \frac{1}{4} \\ &= 5\frac{4 - 2 + 1}{4} \\ &= 5\frac{3}{4} \end{aligned}$$

\]

Solve Question 7

\[

$$\begin{aligned} 5 - 4\frac{3}{4} + \frac{1}{4} &= \frac{1}{4} + \frac{1}{4} \\ &= \frac{2}{4} \\ &= \frac{1}{2} \end{aligned}$$

\]

Solve Question 8

\[

$$\begin{aligned} 3 - \frac{1}{5} - \frac{7}{10} &= 2\frac{10}{10} - \frac{2}{10} - \frac{7}{10} \\ &= 2\frac{10 - 2 - 7}{10} \\ &= 2\frac{1}{10} \end{aligned}$$

\]
</reasoning>

<answer>

Question 5

\[

$$\begin{aligned} &5 - \frac{2}{3} + \frac{1}{2} \\ &= 4\frac{\mathbf{6}}{6} - \frac{4}{6} + \frac{3}{6} \\ &= 4\frac{5}{6} \end{aligned}$$

\]

Question 6

\[

$$\begin{aligned} &6 - \frac{1}{2} + \frac{1}{4} \\ &= 5\frac{3}{4} \end{aligned}$$

\]

Question 7

\[

$$\begin{aligned} &5 - 4\frac{3}{4} + \frac{1}{4} \\ &= \frac{1}{2} \end{aligned}$$

\]

Question 8

\[

$$\begin{aligned} &3 - \frac{1}{5} - \frac{7}{10} \\ &= 2\frac{1}{10} \end{aligned}$$

\]
</answer>

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Answer:

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<reasoning>

Solve Question 5

\[

$$\begin{aligned} 5 - \frac{2}{3} + \frac{1}{2} &= 4\frac{6}{6} - \frac{4}{6} + \frac{3}{6} \\ &= 4\frac{6 - 4 + 3}{6} \\ &= 4\frac{5}{6} \end{aligned}$$

\]
The missing value in the box is \(6\).

Solve Question 6

\[

$$\begin{aligned} 6 - \frac{1}{2} + \frac{1}{4} &= 5\frac{4}{4} - \frac{2}{4} + \frac{1}{4} \\ &= 5\frac{4 - 2 + 1}{4} \\ &= 5\frac{3}{4} \end{aligned}$$

\]

Solve Question 7

\[

$$\begin{aligned} 5 - 4\frac{3}{4} + \frac{1}{4} &= \frac{1}{4} + \frac{1}{4} \\ &= \frac{2}{4} \\ &= \frac{1}{2} \end{aligned}$$

\]

Solve Question 8

\[

$$\begin{aligned} 3 - \frac{1}{5} - \frac{7}{10} &= 2\frac{10}{10} - \frac{2}{10} - \frac{7}{10} \\ &= 2\frac{10 - 2 - 7}{10} \\ &= 2\frac{1}{10} \end{aligned}$$

\]
</reasoning>

<answer>

Question 5

\[

$$\begin{aligned} &5 - \frac{2}{3} + \frac{1}{2} \\ &= 4\frac{\mathbf{6}}{6} - \frac{4}{6} + \frac{3}{6} \\ &= 4\frac{5}{6} \end{aligned}$$

\]

Question 6

\[

$$\begin{aligned} &6 - \frac{1}{2} + \frac{1}{4} \\ &= 5\frac{3}{4} \end{aligned}$$

\]

Question 7

\[

$$\begin{aligned} &5 - 4\frac{3}{4} + \frac{1}{4} \\ &= \frac{1}{2} \end{aligned}$$

\]

Question 8

\[

$$\begin{aligned} &3 - \frac{1}{5} - \frac{7}{10} \\ &= 2\frac{1}{10} \end{aligned}$$

\]
</answer>

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