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3) $nn^{3} \\cdot 4m^{4}n^{3}$

Question

  1. $nn^{3} \cdot 4m^{4}n^{3}$

Explanation:

Step1: Simplify \( nn^3 \)

Using the rule of exponents \( a^m \cdot a^n = a^{m + n} \), for \( n \cdot n^3 \), we have \( n^{1 + 3}=n^4 \).

Step2: Multiply with \( 4m^4n^3 \)

Now, multiply \( n^4 \) with \( 4m^4n^3 \). Using the commutative property and the exponent rule again, we get \( 4m^4 \cdot (n^4 \cdot n^3)=4m^4n^{4 + 3}=4m^4n^7 \).

Answer:

\( 4m^4n^7 \)