Question

1. $-x^{3}+1x = 0$

Explanation:

Step1: Factor out x

$x(-x^{2}+1)=0$

Step2: Factor the quadratic term

$x(1 - x)(1 + x)=0$

Step3: Set each factor equal to zero

If $x=0$, the equation holds. If $1 - x=0$, then $x = 1$. If $1+x=0$, then $x=-1$.

Answer:

$x = 0,x = 1,x=-1$