Question

1. $2(n - 1) = -14$
2. $5r - 1 = -21$
3. $-3(-5 + m) = 27$
4. $\frac{k}{5} - 2 = 0$
5. $-3(4 + v) = -24$

Explanation:

Problem 2: Solve for $n$

Step1: Divide both sides by 2

$\frac{2(n-1)}{2} = \frac{-14}{2}$
$n-1 = -7$

Step2: Add 1 to both sides

$n-1+1 = -7+1$
$n = -6$

Problem 4: Solve for $r$

Step1: Add 1 to both sides

$5r-1+1 = -21+1$
$5r = -20$

Step2: Divide both sides by 5

$\frac{5r}{5} = \frac{-20}{5}$
$r = -4$

Problem 6: Solve for $m$

Step1: Divide both sides by -3

$\frac{-3(-5+m)}{-3} = \frac{27}{-3}$
$-5+m = -9$

Step2: Add 5 to both sides

$-5+m+5 = -9+5$
$m = -4$

Problem 8: Solve for $k$

Step1: Add 2 to both sides

$\frac{k}{5}-2+2 = 0+2$
$\frac{k}{5} = 2$

Step2: Multiply both sides by 5

$\frac{k}{5} \times 5 = 2 \times 5$
$k = 10$

Problem 10: Solve for $v$

Step1: Divide both sides by -3

$\frac{-3(4+v)}{-3} = \frac{-24}{-3}$
$4+v = 8$

Step2: Subtract 4 from both sides

$4+v-4 = 8-4$
$v = 4$

Answer:

1. $n = -6$
2. $r = -4$
3. $m = -4$
4. $k = 10$
5. $v = 4$