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Question
- $w^{2}=\frac{49}{81}$
Step1: Take square - root of both sides
$w=\pm\sqrt{\frac{49}{81}}$
Step2: Simplify the square - root
Since $\sqrt{\frac{49}{81}}=\frac{\sqrt{49}}{\sqrt{81}}$, and $\sqrt{49} = 7$, $\sqrt{81}=9$, then $w=\pm\frac{7}{9}$
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$w = \frac{7}{9}$ or $w=-\frac{7}{9}$