math exploration 5

solve $ax + 3 = 12$ for $x$, where $a \
eq 0$. (use $a$ to represent $x$)

practice 5

solve $2x + 3b = 9$ for $x$. (use $b$ to represent $x$)

exit ticket

1 the solution of $x - 1 = 3 - x$ is _____

Question

math exploration 5

solve $ax + 3 = 12$ for $x$, where $a \
eq 0$. (use $a$ to represent $x$)

practice 5

solve $2x + 3b = 9$ for $x$. (use $b$ to represent $x$)

exit ticket

1 the solution of $x - 1 = 3 - x$ is _____

Accepted Answer

{ "quality": "clear", "question_count": 3, "skills_matched": [ "step_cot", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Solving Linear Equations", "Solving Literal Equations" ], "new_concepts": [], "current_concepts": [ "Solving Linear Equations", "Solving Literal Equations" ] } ## Solve the first literal equation for x $$ \begin{aligned} ax + 3 &= 12 \ ax &= 9 \ x &= \frac{9}{a} \end{aligned} $$ ## Solve the second literal equation for x $$ \begin{aligned} 2x + 3b &= 9 \ 2x &= 9 - 3b \ x &= \frac{9 - 3b}{2} \end{aligned} $$ ## Solve the linear equation for x $$ \begin{aligned} x - 1 &= 3 - x \ 2x - 1 &= 3 \ 2x &= 4 \ x &= 2 \end{aligned} $$ ## Question 1 The solution is $x = \frac{9}{a}$. ## Question 2 The solution is $x = \frac{9 - 3b}{2}$. ## Question 3 The solution of $x - 1 = 3 - x$ is 2. { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Solving Literal Equations" ] }

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Solve the first literal equation for x

Solve the second literal equation for x

Solve the linear equation for x

Answer:

Question 1

Question 2

Question 3