Question

math exploration 1

solve the equation: (10 - 4x = x - 5).

practice 1

sat if (5x + 1 = 3x - 6), what is the value of (6x - 1)?
a. (-20)
b. (-21)
c. (-22)
d. (20)

concept 2: solving equations with parentheses

if there are some parentheses in the equation, we should remove them before move the terms.

think academy

math exploration 2

solve the following equations:
(1) (5(x - 1) + 3 = 3x - 3).
(2) (2x - 5(3 - 2x) = 9x).

practice 2

1 solve the following equations:
(1) (2(3x - 2) + 1 = 8x).
(x = \underline{\quad\quad})
(2) (2x - 12 = -3(x - 1)).
(x = \underline{\quad\quad})

2 sat if (x) is the solution to the equation (3(2x - 6) - 12 = 4(x - 3) + 6), what is the value of (x - 3)?
a. (-9)
b. (-15)
c. (9)
d. (15)

Explanation:

Solve Math Exploration 1

Solve \(10 - 4x = x - 5\):

$$
LATEXBLOCK0
$$

Solve Practice 1

Solve \(5x + 1 = 3x - 6\) and find \(6x - 1\):

$$
LATEXBLOCK1
$$

Solve Math Exploration 2

Solve (1) \(5(x - 1) + 3 = 3x - 3\) and (2) \(2x - 5(3 - 2x) = 9x\):

$$
LATEXBLOCK2
$$

Solve Practice 2 Question 1

Solve (1) \(2(3x - 2) + 1 = 8x\) and (2) \(2x - 12 = -3(x - 1)\):

$$
LATEXBLOCK3
$$

Solve Practice 2 Question 2

Solve \(3(2x - 6) - 12 = 4(x - 3) + 6\) and find \(x - 3\):

$$
LATEXBLOCK4
$$

Answer:

Section	Question / Problem	Answer
Practice 1	If \(5x + 1 = 3x - 6\), value of \(6x - 1\)	C. \(-22\)
Math Exploration 2	(1) Solve \(5(x - 1) + 3 = 3x - 3\)	\(x = -0.5\)
Math Exploration 2	(2) Solve \(2x - 5(3 - 2x) = 9x\)	\(x = 5\)
Practice 2 - Q1	(1) Solve \(2(3x - 2) + 1 = 8x\)	\(x = -1.5\)
Practice 2 - Q1	(2) Solve \(2x - 12 = -3(x - 1)\)	\(x = 3\)
Practice 2 - Q2	If \(3(2x - 6) - 12 = 4(x - 3) + 6\), value of \(x - 3\)	C. \(9\)