Question

match each pair of angle measures of a triangle with the remaining angle measure.
33 degrees 65 degrees 62 degrees 38 degrees
119 degrees and 23 degrees
96 degrees and 51 degrees
28 degrees and 87 degrees
16 degrees and 102 degrees

Explanation:

Step1: Recall the sum of angles in a triangle

The sum of the interior angles of a triangle is \(180^{\circ}\). So, if two angles \(A\) and \(B\) are given, the third angle \(C = 180-(A + B)\)

Step2: Calculate for \(119^{\circ}\) and \(23^{\circ}\)

\(C=180-(119 + 23)=180 - 142=38^{\circ}\)

Step3: Calculate for \(96^{\circ}\) and \(51^{\circ}\)

\(C=180-(96 + 51)=180 - 147=33^{\circ}\)

Step4: Calculate for \(28^{\circ}\) and \(87^{\circ}\)

\(C=180-(28 + 87)=180 - 115=65^{\circ}\)

Step5: Calculate for \(16^{\circ}\) and \(102^{\circ}\)

\(C=180-(16 + 102)=180 - 118=62^{\circ}\)

Answer:

119 degrees and 23 degrees \(\to\) 38 degrees
96 degrees and 51 degrees \(\to\) 33 degrees
28 degrees and 87 degrees \(\to\) 65 degrees
16 degrees and 102 degrees \(\to\) 62 degrees