Question

martin puts two bowls of fruit out for his friends. the bowl of grapes has 9 green grapes and 16 red grapes. the bowl of tangerines has 7 seeded and 3 seedless tangerines. martins friend chooses a random grape and a random tangerine. what is the probability that she chooses a green grape and a seedless tangerine? enter the answer in the box.

Explanation:

Step1: Calculate grape - probability

Find the probability of choosing a green grape. Total grapes are \(9 + 16=25\). Probability of choosing a green grape \(P(G)=\frac{9}{25}\).

Step2: Calculate tangerine - probability

Find the probability of choosing a seedless tangerine. Total tangerines are \(7 + 3 = 10\). Probability of choosing a seedless tangerine \(P(S)=\frac{3}{10}\).

Step3: Calculate combined - probability

Since the events of choosing a grape and a tangerine are independent, the probability of both events occurring is the product of their individual probabilities. \(P = P(G)\times P(S)=\frac{9}{25}\times\frac{3}{10}=\frac{27}{250}\).

Answer:

\(\frac{27}{250}\)