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a marine biologist claims that the mean length of mature female pink se…

Question

a marine biologist claims that the mean length of mature female pink seaperch is different in fall and winter. a sample of 18 mature female pink seaperch collected in fall has a mean length of 111 millimeters and a standard deviation of 15 millimeters. a sample of 8 mature female pink seaperch collected in winter has a mean length of 108 millimeters and a standard deviation of 9 millimeters. at α = 0.20, can you support the marine biologist’s claim? assume the population variances are equal. assume the samples are random and independent, and the populations are normally distributed. complete parts (a) through (e) below. (a) identify the claim and state h₀ and hₐ. which is the correct claim below? a. “the mean length of mature female pink seaperch is the same in fall and winter.” b. “the mean length of mature female pink seaperch is greater in the fall than in the winter.” c. “the mean length of mature female pink seaperch is different in fall and winter.” d. “the mean length of mature female pink seaperch is greater in the winter than in the fall.” what are h₀ and hₐ? the null hypothesis, h₀, is μ₁ = μ₂. the alternative hypothesis, hₐ, is μ₁ ≠ μ₂. which hypothesis is the claim? the alternative hypothesis, hₐ the null hypothesis, h₀

Explanation:

Brief Explanations

The marine biologist's claim is that the mean length differs between fall and winter, which is a two - tailed test. The null hypothesis \(H_0\) assumes no difference (\(\mu_1=\mu_2\)), and the alternative hypothesis \(H_a\) (\(\mu_1
eq\mu_2\)) represents the claim of a difference. So the claim is the alternative hypothesis.

Answer:

The alternative hypothesis, \(H_a\)