Question

the man in the red shirt has a voice frequency of 100 hz. mathematically, how does the wavelength compare as the voice travels through the air, versus through the door. (1 point) not enough information is provided to solve. the wavelength is longer in the air than it is in the door the wavelength is the same in the air and in the door. the wavelength is longer in the door than in the air

Explanation:

To compare wavelengths, we use the wave equation \( v = f\lambda \) (where \( v \) is velocity, \( f \) is frequency, \( \lambda \) is wavelength). Frequency (\( f = 100 \, \text{Hz} \)) is constant for the same sound source. Sound travels faster in solids (door, a solid) than in gases (air). Rearranging the formula: \( \lambda=\frac{v}{f} \). Since \( f \) is constant and \( v_{\text{door}} > v_{\text{air}} \), \( \lambda_{\text{door}} > \lambda_{\text{air}} \). So the wavelength is longer in the door than in the air.

Answer:

The wavelength is longer in the door than in the air