Question

1. machine trades a $\frac{5}{16}$-in. bolt weighs 0.43 lb. how many bolts are there in a keg containing 125 lb of bolts?

Explanation:

Step1: Identify the operation

We need to divide the total weight by the weight of one bolt.

Step2: Set up the division

Let $n$ be the number of bolts. We have $n=\frac{125}{0.43}$.

Step3: Calculate the result

$n=\frac{125}{0.43}\approx290.7$
Since we can't have a fraction of a bolt, we take the whole - number part. So we consider 290 bolts (rounding down as we can't have a partial bolt in this context).

Answer:

290