QUESTION IMAGE
Question
a machine at a bakery is pouring out flour. the graph shows the amount of flour (in grams) in the machine versus time (in minutes). (a) choose the statement that best describes how the time and amount of flour are related. then fill in the blank. as time increases, the amount of flour in the machine decreases. at what rate is the amount of flour decreasing? \boxed{} grams per minute as time increases, the amount of flour in the machine increases. at what rate is the amount of flour increasing? \boxed{} grams per minute (b) what is the amount of flour in the machine at 0 minutes? \boxed{} grams
Step1: Analyze the graph trend
The graph shows a line with a negative slope (going down from left to right), so as time (x - axis) increases, the amount of flour (y - axis) decreases. So we choose the first statement: "As time increases, the amount of flour in the machine decreases."
Step2: Find two points on the line
From the graph, we can identify two points. Let's assume the points are \((0, 630)\) and \((7, 0)\) (since at \(x = 0\) (0 minutes), \(y = 630\) grams and at \(x=7\) minutes, \(y = 0\) grams).
Step3: Calculate the rate of decrease
The rate of change (slope) is given by \(\frac{\Delta y}{\Delta x}=\frac{y_2 - y_1}{x_2 - x_1}\). Here, \(y_1 = 630\), \(y_2=0\), \(x_1 = 0\), \(x_2 = 7\). So the slope is \(\frac{0 - 630}{7-0}=\frac{- 630}{7}=- 90\). The negative sign indicates a decrease, so the rate of decrease is \(90\) grams per minute.
Step4: Find the amount at 0 minutes
From the graph, when \(x = 0\) (time = 0 minutes), the \(y\) - value (amount of flour) is \(630\) grams.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
s:
(a) Statement: As time increases, the amount of flour in the machine decreases. Rate of decrease: \(90\) grams per minute.
(b) Amount at 0 minutes: \(630\) grams.
(For part (a) first blank: "As time increases, the amount of flour in the machine decreases."; second blank: \(90\); For part (b): \(630\))