Question

look at this equation:
$s^3 = 27$
what is $s$, the cube root of 27?
$s = \square$

Explanation:

Step1: Recall the definition of cube root

The cube root of a number \( x \) is a number \( y \) such that \( y^3 = x \). So we need to find a number \( s \) where \( s^3 = 27 \).

Step2: Find the number whose cube is 27

We know that \( 3\times3\times3 = 3^3 = 27 \). So the cube root of 27 is 3.

Answer:

\( s = 3 \)