Question

look at this diagram:
if \\(overleftrightarrow{fh}\\) and \\(overleftrightarrow{ik}\\) are parallel lines and \\(m\angle ijg = 121^{circ}\\), what is \\(m\angle kjg\\)?
submit
\\(\square\\)\\(\circ\\)

Explanation:

Step1: Use the property of adjacent angles

Adjacent angles on a straight line sum to \(180^{\circ}\).
If \(m\angle IJG = 121^{\circ}\), and \(\angle IJG\) and \(\angle KJG\) are adjacent angles on a straight line.
Let \(m\angle KJG=x\). Then \(x + 121^{\circ}=180^{\circ}\).

Step2: Solve for \(x\)

Subtract \(121^{\circ}\) from both sides of the equation \(x+121^{\circ}=180^{\circ}\).
\(x=180^{\circ}- 121^{\circ}\).
\(x = 59^{\circ}\).

Answer:

\(59\)