Question

a light bulb has a resistance of 4.0 ohms and a maximum current of 16.1 a. how much voltage can be applied before the bulb will break?
answer
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14
what are the units for your answer?
select one:
volts
ohms
amps

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $V = I \times R$, where $V$ is voltage, $I$ is current, $R$ is resistance.

Step2: Plug in the values

$I = 16.1\ \text{A}$, $R = 4.0\ \Omega$. Calculate $V = 16.1 \times 4.0$.

Step3: Compute the result

$16.1 \times 4.0 = 64.4$.

for Units:
Voltage is measured in volts (V) when using Ohm's Law with current in amps (A) and resistance in ohms ($\Omega$).

Answer:

64.4