Question

lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. what is the approximate vertical component of the initial velocity?
0.5 m/s
0.87 m/s
12.5 m/s
21.7 m/s

Explanation:

Step1: Recall velocity - component formula

The formula for the vertical - component of an initial velocity $v_0$ thrown at an angle $\theta$ is $v_{0y}=v_0\sin\theta$.

Step2: Substitute given values

Given $v_0 = 25\ m/s$ and $\theta = 60^{\circ}$, and $\sin60^{\circ}=\frac{\sqrt{3}}{2}\approx0.866$. Then $v_{0y}=25\times\sin60^{\circ}=25\times0.866 = 21.65\ m/s\approx21.7\ m/s$.

Answer:

D. 21.7 m/s