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lesson 8.8 homework name 1. find the area of the shaded sector. round y…

Question

lesson 8.8 homework
name

  1. find the area of the shaded sector. round your answer to the nearest tenth.

(image of a circle with radius 3 cm and central angle 117° for the shaded sector)

  1. find the area of the shaded sector. round your answer to the nearest tenth.

(image of a circle with radius 7 in and central angle 141° for the shaded sector)

  1. the shaded sector has an area of 24π square inches. find the central angle of the sector, θ.

(image of a circle with radius 12 in and shaded sector with central angle θ)

Explanation:

Problem 1:

Step 1: Recall the formula for the area of a sector

The formula for the area of a sector of a circle is \( A=\frac{\theta}{360}\times\pi r^{2} \), where \( \theta \) is the central angle in degrees and \( r \) is the radius of the circle.

Step 2: Identify the values of \( \theta \) and \( r \)

From the diagram, \( \theta = 117^{\circ} \) and \( r = 3\space\text{cm} \).

Step 3: Substitute the values into the formula

Substitute \( \theta = 117^{\circ} \) and \( r = 3\space\text{cm} \) into the formula:
\( A=\frac{117}{360}\times\pi\times(3)^{2} \)
First, calculate \( (3)^{2}=9 \). Then, \( \frac{117}{360}\times\pi\times9=\frac{117\times9\pi}{360}=\frac{1053\pi}{360} \)
Simplify \( \frac{1053}{360}=\frac{117}{40} = 2.925 \)
So, \( A = 2.925\pi\approx2.925\times3.1416\approx9.2\space\text{cm}^2 \) (rounded to the nearest tenth)

Step 1: Recall the formula for the area of a sector

The formula for the area of a sector of a circle is \( A=\frac{\theta}{360}\times\pi r^{2} \), where \( \theta \) is the central angle in degrees and \( r \) is the radius of the circle.

Step 2: Identify the values of \( \theta \) and \( r \)

From the diagram, \( \theta = 141^{\circ} \) and \( r = 7\space\text{in} \).

Step 3: Substitute the values into the formula

Substitute \( \theta = 141^{\circ} \) and \( r = 7\space\text{in} \) into the formula:
\( A=\frac{141}{360}\times\pi\times(7)^{2} \)
First, calculate \( (7)^{2}=49 \). Then, \( \frac{141}{360}\times\pi\times49=\frac{141\times49\pi}{360}=\frac{6909\pi}{360} \)
Simplify \( \frac{6909}{360}=\frac{2303}{120}\approx19.1917 \)
So, \( A=\frac{2303}{120}\pi\approx19.1917\times3.1416\approx60.3\space\text{in}^2 \) (rounded to the nearest tenth)

Step 1: Recall the formula for the area of a sector

The formula for the area of a sector of a circle is \( A=\frac{\theta}{360}\times\pi r^{2} \), where \( \theta \) is the central angle in degrees and \( r \) is the radius of the circle. We need to solve for \( \theta \).

Step 2: Identify the values of \( A \) and \( r \)

From the problem, \( A = 24\pi\space\text{square inches} \) and \( r = 12\space\text{in} \).

Step 3: Substitute the values into the formula and solve for \( \theta \)

Substitute \( A = 24\pi \) and \( r = 12\space\text{in} \) into the formula:
\( 24\pi=\frac{\theta}{360}\times\pi\times(12)^{2} \)
First, divide both sides by \( \pi \):
\( 24=\frac{\theta}{360}\times144 \)
Then, solve for \( \theta \):
\( \frac{\theta}{360}=\frac{24}{144}=\frac{1}{6} \)
Multiply both sides by \( 360 \):
\( \theta=\frac{1}{6}\times360 = 60^{\circ} \)

Answer:

The area of the shaded sector is approximately \( 9.2\space\text{cm}^2 \)

Problem 2: