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lesson 4 exit ticket maya goes rock climbing, and she rappels down a cl…

Question

lesson 4 exit ticket

maya goes rock climbing, and she rappels down a cliff. the bottom of the cliff is 45 feet below sea level. if maya is currently 2.8 feet below sea level, how many more feet must she rappel down to reach the bottom of the cliff?

show or explain your work in the space below:

equation that matches the story:

equation that matches your work:

answer:

Explanation:

Identify the given values

The bottom of the cliff is \(45\text{ feet}\) below sea level, represented as \(-45\).
Maya is currently \(2.8\text{ feet}\) below sea level, represented as \(-2.8\).

Define the target variable

Let \(x\) be the additional distance in feet Maya must rappel down.
Rappeling down represents a negative change in elevation, so we subtract \(x\).

Write the story equation

The story starts at Maya's current elevation and subtracts the distance she rappels to reach the bottom:

$$-2.8 - x = -45$$

Write the work equation

To find the remaining distance \(x\), we calculate the difference between her current position and the target:

$$x = -2.8 - (-45)$$

Simplifying this expression:

$$x = 42.2$$

State the final answer

Maya must rappel down an additional \(42.2\text{ feet}\).

Answer:

Equation that matches the story:

$$-2.8 - x = -45$$

Equation that matches your work:

$$x = -2.8 - (-45)$$

Answer:
\(42.2\text{ feet}\)