Question

lesson 21 | session 1
look at the hanger diagram.
a. what is the value of z in the hanger diagram? show your work.
olution
check your answer to problem 3a

Explanation:

Step1: Count the number of 1s on the left

There are 7 blocks with value 1 on the left, so the total weight on the left is \( 7\times1 = 7 \).

Step2: Set up the equation for the hanger (equilibrium)

The hanger is in equilibrium, so the weight on the left equals the weight on the right. The right side has \( z + 1 \) (since there's a block with value \( z \) and a block with value 1). So we set up the equation:
\( z + 1 = 7 \)

Step3: Solve for \( z \)

Subtract 1 from both sides of the equation:
\( z = 7 - 1 \)
\( z = 6 \)

Answer:

The value of \( z \) is \( 6 \).