Question

the length of a rectangle is twice its width. if the perimeter of the rectangle is 60 m, find its length and width. length: m width: m

Explanation:

Step1: Let the width be \(x\)

Let the width of the rectangle be \(x\) meters. Since the length is twice the width, the length is \(2x\) meters.

Step2: Use the perimeter formula

The perimeter formula of a rectangle is \(P = 2\times(\text{length}+\text{width})\). Given \(P = 60\) m, we have \(60=2\times(2x + x)\).
Simplify the right - hand side: \(60 = 2\times3x\), so \(60=6x\).

Step3: Solve for \(x\)

Divide both sides of the equation \(60 = 6x\) by 6: \(x=\frac{60}{6}=10\).

Answer:

length: \(20\) m
width: \(10\) m