Question

the length of a rectangle is 4 ft longer than its width, if the perimeter of the rectangle is 60 ft, find its length and width.
length: \\(\square\\) ft
width: \\(\square\\) ft

Explanation:

Step1: Define variables

Let width = $w$ ft, length = $w + 4$ ft.

Step2: Use perimeter formula

Perimeter = $2(length + width) = 60$. Substitute: $2((w + 4) + w) = 60$.

Step3: Simplify equation

$2(2w + 4) = 60 \implies 4w + 8 = 60$.

Step4: Solve for w

$4w = 52 \implies w = 13$.

Step5: Find length

Length = $13 + 4 = 17$.

Answer:

Length: 17 ft
Width: 13 ft