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learn more remarks the normal force $vec{n}$, the gravitational force $mvec{g}$, and the upward component of the applied force do no work on the sled because theyre perpendicular to the displacement. the mass of the sled didnt come into play here, but it is important when the effects of friction must be calculated and in the work - energy theorem. question how does the answer for the work done by the applied force change if the load is doubled? the work is doubled. the work is halved. the work is the same. explain. this answer has not been graded yet. practice it use the worked example above to help you solve this problem. an eskimo returning from a successful fishing trip pulls a sled loaded with salmon. the total mass of the sled and salmon is 50.0 kg, and the eskimo exerts a force of 1.00×10² n on the sled by pulling on the rope. (a) how much work does he do on the sled if the rope is horizontal to the ground ($\theta = 0^{circ}$ in the
Step1: Recall work - formula
The work done by a force $W = Fd\cos\theta$, where $F$ is the force, $d$ is the displacement and $\theta$ is the angle between the force and the displacement. In the case of the work - done by the applied force, if the force applied and the displacement are in the same direction ($\theta = 0^{\circ}$, $\cos\theta=1$), $W = Fd$. The work done by the applied force depends only on the applied force $F$ and the displacement $d$, and not on the mass (load) of the sled. Doubling the load does not change the applied force or the displacement.
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The work is the same.