Question

b) le réservoir d’une autre lampe a une capacité de 0,16 l. peut-on le remplir 27 fois à l’aide de la bouteille ? explique ta réponse.
réponse :

Explanation:

Step1: Identify Missing Info

The problem asks if a lamp reservoir (0.16 L) can be filled 27 times with a bottle, but the bottle's capacity is not provided (partially visible text, likely from a previous part). Without the bottle's volume, we can't calculate total needed (0.16×27) or compare to bottle's capacity.

Step2: Explain Requirement

To solve, we need the bottle's volume (let’s call it \( V \) L). Calculate total volume needed: \( 0.16 \times 27 = 4.32 \) L. Then check if \( V \geq 4.32 \) L. Since \( V \) is missing, we can’t answer yet.

Answer:

To determine if the reservoir can be filled 27 times, we need the bottle’s capacity (from the previous part, not shown here).

1. Calculate total volume needed: \( 0.16 \, \text{L/ fill} \times 27 \, \text{fills} = 4.32 \, \text{L} \).
2. Compare to the bottle’s volume (\( V \)): If \( V \geq 4.32 \, \text{L} \), then yes; otherwise, no.

Since the bottle’s capacity is missing, we cannot conclude without it.