Question

a 0.2 - kilogram softball is thrown toward a catchers mitt. the ball is accelerating at a rate of 8 meters per second squared. with what force will the ball hit the catchers mitt? (1 point)
7.8 n
40 n
8.2 n
1.6 n

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration.

Step2: Substitute the given values

Given \(m = 0.2\space kg\) and \(a=8\space m/s^{2}\). Substitute into \(F = ma\), so \(F=(0.2)(8)\).

Step3: Calculate the force

\(F = 1.6\space N\)

Answer:

1.6 N