Question

jump to level 1
the mean of three numbers, value1, value2, and value3, is given by meanofthree = \frac{(value1 + value2 + value3)}{3.0}. read double variables value1, value2, and value3 from input, respectively. then, compute meanofthree using the formula. finally, output \mean is \ followed by the value of meanofthree to four digits after the decimal point. end with a newline.
ex: if the input is 24.0 36.0 6.0, then the output is:
mean is 22.0000
1 #include <iomanip>
2 #include <iostream>
3 using namespace std;
4
5 int main() {
6
7
8
9 return 0;
10 }

Explanation:

Step1: Include necessary headers

#include <iomanip>
#include <iostream>
using namespace std;

Step2: Declare variables and read input

int main() {
    double value1, value2, value3;
    cin >> value1 >> value2 >> value3;

Step3: Compute the mean

    double meanOfThree = (value1 + value2 + value3) / 3.0;

Step4: Output the result

    cout << fixed << setprecision(4) << "Mean is " << meanOfThree << endl;
    return 0;
}

Answer:

#include <iomanip>
#include <iostream>
using namespace std;

int main() {
    double value1, value2, value3;
    cin >> value1 >> value2 >> value3;
    double meanOfThree = (value1 + value2 + value3) / 3.0;
    cout << fixed << setprecision(4) << "Mean is " << meanOfThree << endl;
    return 0;
}