Question

john pushes hector on a plastic toboggan. the free - body diagram is shown. what is the net force acting on hector and the toboggan? $f_n = 490\\ n$ $f_f=-245\\ n$ $f_t = 735\\ n$ $f_g=-490\\ n$ 245 n 735 n 490 n 980 n

Explanation:

Step1: Calculate net - force in x - direction

$F_{netx}=F_t + F_f=735+( - 245)=490$ N

Step2: Calculate net - force in y - direction

$F_{nety}=F_N+F_g = 490+( - 490)=0$ N

Step3: Calculate the magnitude of the net force

$F_{net}=\sqrt{F_{netx}^2 + F_{nety}^2}=\sqrt{490^2+0^2}=490$ N

Answer:

490 N