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john estimates the value of his car over time. the equation for the lin…

Question

john estimates the value of his car over time. the equation for the line of best fit is approximated as ( y = - 2.9 x + 15.7 ) where ( y ) represents the value, in thousands of dollars. what values complete the residual table? ( a = ) ( b = ) ( c = ) ( d = )

Explanation:

Step1: Recall Residual Formula

Residual = Given Value - Predicted Value. Also, Predicted Value is from \( y = -2.9x + 15.7 \), where \( x \) is age (years).

Step2: Find \( a \) (Predicted Value when \( x = 1 \))

Use the line of best fit: \( y = -2.9(1) + 15.7 \)
\( y = -2.9 + 15.7 = 12.8 \)? Wait, no—wait, residual is Given - Predicted. Wait, residual for \( x = 1 \) is \( 15 - a = 0.2 \)? Wait, no, wait the table: Age 1, Given Value 15, Residual 0.2. So Residual = Given - Predicted → \( 15 - a = 0.2 \) → \( a = 15 - 0.2 = 14.8 \). Wait, but also check the line of best fit. Wait, maybe I mixed up. Wait, the line of best fit is \( y = -2.9x + 15.7 \). For \( x = 1 \), \( y = -2.9(1) + 15.7 = 12.8 \)? But that contradicts the residual. Wait, no, maybe the residual is Predicted - Given? No, residual is usually (Observed - Predicted). Let's check the last row: Age 5, Given 4, Predicted 3.2, Residual 0.8. 4 - 3.2 = 0.8. Yes! So Residual = Given Value - Predicted Value. So for Age 1: Given 15, Residual 0.2 → 15 - a = 0.2 → a = 15 - 0.2 = 14.8? Wait, but let's check the line of best fit. Wait, maybe the line of best fit is \( y = -2.9x + 15.7 \). Wait, for \( x = 1 \), \( y = -2.9(1) + 15.7 = 12.8 \). But that's not 14.8. Wait, maybe a typo? Wait, no, the last row: Age 5, Predicted 3.2. Let's check the line: \( y = -2.9(5) + 15.7 = -14.5 + 15.7 = 1.2 \)? Wait, no, 3.2? Wait, maybe the equation is \( y = -2.9x + 15.7 \)? Wait, 5(-2.9) = -14.5, 15.7 -14.5 = 1.2. But the table says Predicted Value for Age 5 is 3.2. Wait, maybe the equation is \( y = -2.9x + 15.7 \)? Wait, no, maybe the equation is \( y = -2.9x + 15.7 \)? Wait, let's re-express. Wait, the problem says "the equation for the line of best fit is approximated as \( y = -2.9x + 15.7 \), where \( y \) represents the value, in thousands of dollars." Wait, for Age 5 (x=5), y should be -2.95 +15.7 = -14.5 +15.7 = 1.2. But the table has Predicted Value 3.2. So there's a mistake? Wait, no, maybe the equation is \( y = -2.9x + 15.7 \)? Wait, no, maybe I misread the equation. Wait, maybe it's \( y = -2.9x + 15.7 \)? Wait, let's check Age 2: Predicted Value 11.9. Let's plug x=2: \( y = -2.9(2) +15.7 = -5.8 +15.7 = 9.9 \). But the table says Predicted Value 11.9. So clearly, the equation must be \( y = -2.9x + 15.7 \)? No, that's not matching. Wait, maybe the equation is \( y = -2.9x + 15.7 \)? Wait, no, maybe the equation is \( y = -2.9x + 15.7 \)? Wait, let's check the last row: Age 5, Predicted 3.2. Let's solve for the equation. If x=5, y=3.2: 3.2 = -2.95 + b → 3.2 = -14.5 + b → b=17.7. Ah! So the equation is \( y = -2.9x + 17.7 \). Yes! That makes sense. Because -2.95 +17.7 = -14.5 +17.7 = 3.2. Yes! So the equation is \( y = -2.9x + 17.7 \). Okay, that's the correct equation. So let's redo:

Step1: Find \( a \) (Predicted Value when \( x=1 \))

Use \( y = -2.9x + 17.7 \). For \( x=1 \): \( y = -2.9(1) +17.7 = 14.8 \). So \( a = 14.8 \). Let's check residual: Given Value (15) - Predicted Value (14.8) = 0.2. Which matches the table. Good.

Step2: Find \( b \) (Residual for \( x=2 \))

Given Value =12, Predicted Value=11.9 (from table). Residual = Given - Predicted = 12 - 11.9 = 0.1. Wait, but let's check with the equation. For \( x=2 \), Predicted Value is \( y = -2.9(2) +17.7 = -5.8 +17.7 = 11.9 \). So Residual = 12 - 11.9 = 0.1. So \( b = 0.1 \).

Step3: Find \( c \) (Predicted Value when \( x=3 \))

Residual = 0 (Given Value - Predicted Value =0 → Given Value = Predicted Value). Given Value is 9, so Predicted Value \( c = 9 \). Let's check with the equation: \( y = -2.9(…

Answer:

\( a = 14.8 \)
\( b = 0.1 \)
\( c = 9 \)
\( d = -1.1 \)