Question

jeremy was in the park flying a kite. the kite was flying at the end of a string 48 meters long, making an angle of \\(75^{\circ}\\) with the ground. how high was the kite above the ground?

complete the trig ratio.

\\(\sin(75^{\circ}) = \frac{x}{48}\\)

write your answer as a decimal rounded to the nearest hundredth.

jeremys kite is approximately meters above ground.

Explanation:

Set up the trigonometric ratio

$$ \sin(75^\circ) = \frac{BC}{48} $$

Solve for the height BC

$$
LATEXBLOCK0
$$

Round to the nearest hundredth

$$ BC \approx 46.36 $$

Answer:

Question 1

Complete the trig ratio:
<blank>\(\sin\)</blank> \(75^\circ = \frac{\text{BC}}{48}\)

Question 2

Jeremy's kite is approximately <blank>46.36</blank> meters above ground.