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Question
jean stocked her aquarium with 36 freshwater fish, which cost $212. the male fish cost $5 each, while the female fish cost $7 each. find the number of male fish (x) and the number of female fish (y).
solution (
,
)
number of males?
number of females?
Step1: Set up total fish equation
$x + y = 36$
Step2: Set up total cost equation
$5x + 7y = 212$
Step3: Isolate $x$ from Step1
$x = 36 - y$
Step4: Substitute $x$ into cost equation
$5(36 - y) + 7y = 212$
Step5: Simplify to solve for $y$
$180 - 5y + 7y = 212$
$2y = 212 - 180$
$2y = 32$
$y = 16$
Step6: Substitute $y$ to find $x$
$x = 36 - 16 = 20$
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Number of males? 20
Number of females? 16
Solution ($x=20$, $y=16$)