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Question
jackie plants 2 flowers in a planter box. every week, she plants one more flower in the planter box. how many flowers does jackie have in her planter box after 5 weeks? jackie has \boxed{} flowers in her planter box after 5 weeks.
Step1: Identify the sequence pattern
Jackie starts with 2 flowers. Then each week, she plants 1 more. So the number of flowers each week forms an arithmetic sequence: first term \( a_1 = 2 \), common difference \( d = 1 \), and we need the sum after \( n = 5 \) weeks (including the initial planting? Wait, actually, let's think in terms of weeks: Week 0 (initial): 2, Week 1: 3, Week 2: 4, Week 3: 5, Week 4: 6? Wait no, the problem says "after 5 weeks". Wait, initial planting is before any weeks? Wait, the problem says "Jackie plants 2 flowers in a planter box. Every week, she plants one more flower in the planter box. How many flowers does Jackie have in her planter box after 5 weeks?"
So let's list the number of flowers planted each week:
Week 1 (first week after initial): plants 3? Wait no, initial is 2, then every week (so week 1: 2 + 1 = 3, week 2: 3 + 1 = 4, week 3: 4 + 1 = 5, week 4: 5 + 1 = 6, week 5: 6 + 1 = 7? Wait no, maybe the initial is week 0, and we need the total after 5 weeks (so weeks 0 to 5, 6 terms? No, the problem says "after 5 weeks", so maybe the initial is week 0, and then 5 weeks pass, so weeks 0 (initial), week 1, week 2, week 3, week 4, week 5? Wait, no, maybe the initial planting is the start, and then each week after that she plants one more. So the number of flowers each week (including the initial) is:
Week 0 (start): 2
Week 1: 2 + 1 = 3
Week 2: 3 + 1 = 4
Week 3: 4 + 1 = 5
Week 4: 5 + 1 = 6
Week 5: 6 + 1 = 7
Wait, but that's 6 terms. But maybe the problem is that the initial 2 is week 0, and then after 5 weeks, we have week 0 to week 5, which is 6 weeks? No, maybe the initial planting is week 1, and then 5 weeks: week 1: 2, week 2: 3, week 3: 4, week 4: 5, week 5: 6. Wait, that's 5 weeks, but then the total would be the sum of an arithmetic sequence with first term 2, common difference 1, number of terms 5? Wait, no, let's check the problem again: "Jackie plants 2 flowers in a planter box. Every week, she plants one more flower in the planter box. How many flowers does Jackie have in her planter box after 5 weeks?"
So the number of flowers planted each week:
- Week 1 (first week): 2 flowers
- Week 2: 2 + 1 = 3 flowers
- Week 3: 3 + 1 = 4 flowers
- Week 4: 4 + 1 = 5 flowers
- Week 5: 5 + 1 = 6 flowers
Wait, no, that's 5 weeks, but the total number of flowers is the sum of these? Wait, no, maybe she plants 2 initially, then every week after that, she plants one more. So the total number of flowers after n weeks is the sum of the arithmetic series where the first term \( a_1 = 2 \), common difference \( d = 1 \), and number of terms \( n + 1 \) (since initial is week 0, then n weeks). Wait, after 5 weeks, the number of terms is 6 (week 0 to week 5). The formula for the sum of an arithmetic series is \( S_n = \frac{n}{2}(2a_1 + (n - 1)d) \). Wait, if n = 6 (terms), then \( S_6 = \frac{6}{2}(22 + (6 - 1)1) = 3(4 + 5) = 39 = 27 \)? No, that can't be right. Wait, maybe I'm misunderstanding the problem. Maybe "every week, she plants one more flower" means that each week, the number of flowers she plants increases by 1, but the total number of flowers is the sum of the number of flowers planted each week.
Wait, initial planting: 2 flowers (week 0)
Week 1: plants 2 + 1 = 3 flowers
Week 2: plants 3 + 1 = 4 flowers
Week 3: plants 4 + 1 = 5 flowers
Week 4: plants 5 + 1 = 6 flowers
Week 5: plants 6 + 1 = 7 flowers
Wait, no, that would be the number of flowers planted each week, but the total number of flowers is the sum of all these. Wait, no, maybe the problem is that she plants 2 flowers…
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