Question

for items 3 - 5, use the information to answer each question. 3. quadrilateral c(3, 6), d(5, 2), e(2, -1), f(-2, -3) is reflected over the line y = -4 to form cdef. what are the coordinates of cdef? c: (__, ) e: (, ) d: (, ) f: (, __)

Explanation:

Step1: Calculate y - distance

For point $C(3,6)$, distance from $y = 6$ to $y=-4$ is $6-(-4)=10$.

Step2: Find new y - coordinate

New $y$ of $C'$ is $-4 - 10=-14$, $x$ remains $3$, so $C'=(3,-14)$.

Step3: Repeat for other points

For $D(5,2)$, distance is $2 - (-4)=6$, new $y$ is $-4-6=-10$, $D'=(5,-10)$.
For $E(2,-1)$, distance is $-1-(-4) = 3$, new $y$ is $-4 - 3=-7$, $E'=(2,-7)$.
For $F(-2,-3)$, distance is $-3-(-4)=1$, new $y$ is $-4 - 1=-5$, $F'=(-2,-5)$.

Answer:

$C':(3,-14)$
$D':(5,-10)$
$E':(2,-7)$
$F':(-2,-5)$