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Question
isosceles triangles
the vertex angle of an isosceles triangle measures 40°. what is the measure of a base angle?
140°
100°
40°
70°
the measure of each base angle be \(x\). The vertex angle is \(40^{\circ}\). So, \(x + x+40^{\circ}=180^{\circ}\), which simplifies to \(2x=180^{\circ}- 40^{\circ}=140^{\circ}\).
Step3: Solve for \(x\)
Divide both sides of \(2x = 140^{\circ}\) by 2. \(x=\frac{140^{\circ}}{2}=70^{\circ}\).
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\(70^{\circ}\)