Question

an internet research company surveyed 90 online shoppers, each of whom made one purchase today. the company recorded the type of purchase each shopper made. here is a summary.
three shoppers from the survey are selected at random, one at a time without replacement. what is the probability that the first shopper purchased pet supplies and the other two did not?
do not round your intermediate computations. round your final answer to three decimal places.

Explanation:

Step1: Calculate total number of shoppers

Total number of shoppers \( n = 25+34 + 19+12=90 \)

Step2: Calculate probability for first shopper (pet - supplies)

Probability \( P=\frac{\text{Number of pet - supplies shoppers}}{\text{Total number of shoppers}} \)
Number of pet - supplies shoppers \( m = 19 \)
\( P=\frac{19}{90}\approx0.211 \)

Answer:

\( 0.211 \)