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Question
instruction
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proving the sum of the interior angle measures of a
triangle is 180°
given: y || z
prove: m∠5 + m∠2 + m∠6 = 180°
Step1: Use alternate - interior angles
Since \(y\parallel z\), \(\angle1\cong\angle5\) (alternate - interior angles). So \(m\angle1 = m\angle5\).
Step2: Use alternate - interior angles
Also, since \(y\parallel z\), \(\angle3\cong\angle6\) (alternate - interior angles). So \(m\angle3=m\angle6\).
Step3: Use linear - pair property
\(\angle1,\angle2,\angle3\) form a linear pair. So \(m\angle1 + m\angle2+m\angle3=180^{\circ}\) (linear - pair postulate: the sum of angles in a linear pair is \(180^{\circ}\)).
Step4: Substitute
Substitute \(m\angle1\) with \(m\angle5\) and \(m\angle3\) with \(m\angle6\) in the equation \(m\angle1 + m\angle2+m\angle3=180^{\circ}\). We get \(m\angle5 + m\angle2+m\angle6=180^{\circ}\).
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The proof is completed as shown in the steps above.