Question

incorrect
your answer is incorrect.
simplify.
$(w^{-5})^2$
write your answer without using negative exponents.
your answer

Explanation:

Step1: Apply exponent rule

For \((a^m)^n = a^{m\times n}\), here \(a = w\), \(m=-5\), \(n = 2\). So \((w^{-5})^2=w^{-5\times2}=w^{-10}\).

Step2: Convert negative exponent

Using \(a^{-n}=\frac{1}{a^n}\), so \(w^{-10}=\frac{1}{w^{10}}\).

Answer:

\(\frac{1}{w^{10}}\)