Question

incorrect
your answer is incorrect.
simplify.
$v^3 \cdot v \cdot v^{-9}$
write your answer with a positive exponent only.
your answer

Explanation:

Step1: Recall exponent rule for multiplication

When multiplying terms with the same base, we add the exponents. The base here is \( v \), and we have \( v^{3} \cdot v^{1} \cdot v^{-9} \) (since \( v = v^{1} \)).
So, we add the exponents: \( 3 + 1 + (-9) \).

Step2: Calculate the sum of exponents

\( 3 + 1 + (-9) = 4 - 9 = -5 \). So the expression simplifies to \( v^{-5} \).

Step3: Convert negative exponent to positive

Using the rule \( a^{-n}=\frac{1}{a^{n}} \), we convert \( v^{-5} \) to \( \frac{1}{v^{5}} \).

Answer:

\(\frac{1}{v^{5}}\)