Question

identify the relationship between the graphs of these two equations. 6y = 6x + 1 6y = -6x + 1 click on the correct answer. parallel perpendicular neither

Explanation:

Step1: Convert to slope - intercept form

For the first equation \(6y = 6x+1\), divide both sides by 6: \(y=\frac{6x + 1}{6}=x+\frac{1}{6}\). The slope \(m_1 = 1\).
For the second equation \(6y=-6x + 1\), divide both sides by 6: \(y=\frac{-6x + 1}{6}=-x+\frac{1}{6}\). The slope \(m_2=-1\).

Step2: Check slope relationship

Two lines are perpendicular if \(m_1\times m_2=- 1\). Here, \(m_1\times m_2=1\times(-1)=-1\). So the lines are perpendicular.

Answer:

perpendicular