Question

identify the missing daughter in the following nuclear reaction

99 43tc→____+0 -1e

Explanation:

Step1: Apply conservation of atomic number

In a nuclear reaction, the sum of atomic numbers on both sides must be equal. The atomic number of \(Tc\) (Technetium) is \(43\), and for the electron (\(_{-1}^0e\)) the atomic number is \(- 1\). Let the atomic number of the daughter nucleus be \(Z\). Then \(43=Z+( - 1)\), so \(Z = 44\).

Step2: Apply conservation of mass number

The mass number of \(Tc\) is \(99\), and for the electron the mass number is \(0\). Let the mass number of the daughter nucleus be \(A\). Then \(99=A + 0\), so \(A=99\).

Step3: Identify the element

The element with atomic number \(Z = 44\) is \(Ru\) (Ruthenium).

Answer:

\(_{44}^{99}Ru\)