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Question
identify a method to find the area of \\( \triangle qrs \\) given that \\( \overline{q s} \perp \overline{r t} \\). then find the area. show your work
o a) use the distance formula to find the base \\( q s \\) and the height \\( r t \\). \\( q s=\sqrt{18}, r t=\sqrt{72} \\). then use the area formula:
\\( a=\frac{1}{2}(\sqrt{18})(\sqrt{72})=\frac{1}{2}(36) \\). so, the area is 18 units².
o b) use the distance formula to find the base \\( q s \\) and the height \\( r t \\). \\( q s=\sqrt{72}, r t=\sqrt{18} \\). then use the area formula:
\\( a=\frac{1}{2}(\sqrt{72})(\sqrt{18})=\frac{1}{2}(36) \\). so, the area is 18 units².
o c) use the distance formula to find the base \\( q s \\) and the height \\( r t \\). \\( q s=\sqrt{64}, r t=\sqrt{25} \\). then use the area formula:
\\( a=\frac{1}{2}(\sqrt{64})(\sqrt{25})=\frac{1}{2}(40) \\). so, the area is 20 units².
Step1: Calculate the length of \(QS\)
Use the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). For points \(Q(2,4)\) and \(S(8,-2)\), we have \(x_1 = 2,y_1=4,x_2 = 8,y_2=-2\).
Step2: Calculate the length of \(RT\)
Use the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). For points \(R(6,6)\) and \(T(3,3)\), we have \(x_1 = 6,y_1=6,x_2 = 3,y_2=3\).
Step3: Calculate the area of \(\triangle QRS\)
Since \(QS\perp RT\), the area of \(\triangle QRS\) is \(A=\frac{1}{2}\times base\times height\). Here, base \(=QS=\sqrt{72}\) and height \(=RT=\sqrt{18}\)
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A. Use the Distance Formula to find the base \(QS\) and the height \(RT\). \(QS=\sqrt{72}\), \(RT=\sqrt{18}\). Then use the area formula \(A=\frac{1}{2}(\sqrt{72})(\sqrt{18})=\frac{1}{2}(36)=18\) units².