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s.id.b.6: regression 1 1 the table below shows the number of grams of c…

Question

s.id.b.6: regression 1
1 the table below shows the number of grams of carbohydrates, x, and the number of calories, y, of six different foods.

carbohydrates (x)calories (y)
9.5138
10147
688
7108
462

which equation best represents the line of best fit for this set of data?

  1. y = 15x
  2. y = 0.07x
  3. y = 0.1x - 0.4
  4. y = 14.1x + 5.8

Explanation:

Step1: Calculate the mean of \(x\) values

\(\bar{x}=\frac{8 + 9.5+10 + 6+7+4}{6}=\frac{44.5}{6}\approx7.42\)

Step2: Calculate the mean of \(y\) values

\(\bar{y}=\frac{120 + 138+147+88+108+62}{6}=\frac{663}{6}=110.5\)

Step3: Calculate the slope \(m\) using the formula \(m=\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})(y_{i}-\bar{y})}{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}\)

Let's calculate the numerator \(\sum_{i = 1}^{n}(x_{i}-\bar{x})(y_{i}-\bar{y})\):
\((8 - 7.42)(120 - 110.5)+(9.5 - 7.42)(138 - 110.5)+(10 - 7.42)(147 - 110.5)+(6 - 7.42)(88 - 110.5)+(7 - 7.42)(108 - 110.5)+(4 - 7.42)(62 - 110.5)\)
\(=0.58\times9.5 + 2.08\times27.5+2.58\times36.5+( - 1.42)\times(- 22.5)+(-0.42)\times(-2.5)+(-3.42)\times(-48.5)\)
\(=5.51+57.2+94.17 + 31.95+1.05+165.87\)
\(=355.75\)
Let's calculate the denominator \(\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}\):
\((8 - 7.42)^{2}+(9.5 - 7.42)^{2}+(10 - 7.42)^{2}+(6 - 7.42)^{2}+(7 - 7.42)^{2}+(4 - 7.42)^{2}\)
\(=0.58^{2}+2.08^{2}+2.58^{2}+(-1.42)^{2}+(-0.42)^{2}+(-3.42)^{2}\)
\(=0.3364+4.3264+6.6564 + 2.0164+0.1764+11.6964\)
\(=25.2084\)
\(m=\frac{355.75}{25.2084}\approx14.1\)

Step4: Calculate the y - intercept \(b\) using the formula \(b=\bar{y}-m\bar{x}\)

\(b = 110.5-14.1\times7.42\)
\(b=110.5 - 104.622\)
\(b\approx5.8\)
The equation of the line of best - fit is \(y = 14.1x+5.8\)

Answer:

  1. \(y = 14.1x+5.8\)