Question

Question was provided via image upload.

Explanation:

Solve the first section of equivalent fraction pairs

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Solve the second section of equivalent fraction rows

$$
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Note: The last row in the image is \(\frac{4}{5} = \frac{8}{10} = \frac{12}{15} = \frac{16}{20} = \frac{20}{25}\).

Answer:

No.	Problem	Answer
2	\(\frac{3}{4} = \frac{?}{12}\)	\(9\)
3	\(\frac{7}{8} = \frac{?}{32}\)	\(28\)
4	\(\frac{3}{8} = \frac{?}{16}\)	\(6\)
5	\(\frac{1}{5} = \frac{?}{15}\)	\(3\)
6	\(\frac{2}{5} = \frac{?}{25}\)	\(10\)
7	\(\frac{3}{11} = \frac{9}{?}\)	\(33\)
8	\(\frac{4}{9} = \frac{?}{27}\)	\(12\)
9	\(\frac{7}{9} = \frac{?}{27}\)	\(21\)
10	\(\frac{1}{4} = \frac{?}{16}\)	\(4\)
11	\(\frac{2}{3} = \frac{?}{9}\)	\(6\)
12	\(\frac{7}{10} = \frac{14}{?}\)	\(20\)
13	\(\frac{5}{6} = \frac{?}{30}\)	\(25\)
14	\(\frac{1}{3} = \frac{2}{?} = \frac{?}{9} = \frac{4}{?} = \frac{?}{15}\)	\(\frac{1}{3} = \frac{2}{6} = \frac{3}{9} = \frac{4}{12} = \frac{5}{15}\)
15	\(\frac{2}{3} = \frac{?}{6} = \frac{6}{?} = \frac{?}{12} = \frac{10}{?}\)	\(\frac{2}{3} = \frac{4}{6} = \frac{6}{9} = \frac{8}{12} = \frac{10}{15}\)
16	\(\frac{4}{5} = \frac{8}{?} = \frac{?}{15} = \frac{16}{?} = \frac{?}{25}\)	\(\frac{4}{5} = \frac{8}{10} = \frac{12}{15} = \frac{16}{20} = \frac{20}{25}\)