Question

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Explanation:

Question 1

Step1: Recall Newton's second law, \( F = ma \)

Given \( m = 3.5 \, \text{kg} \), \( a = 0.5 \, \text{m/s}^2 \)

Step2: Substitute values into the formula

\( F = 3.5 \times 0.5 \)
\( F = 1.75 \, \text{N} \)

Step1: Use \( F = ma \)

Given \( m = 1000 \, \text{kg} \), \( a = 6 \, \text{m/s}^2 \)

Step2: Calculate force

\( F = 1000 \times 6 \)
\( F = 6000 \, \text{N} \)

Step1: Rearrange \( F = ma \) to \( a = \frac{F}{m} \)

Given \( F = 12 \, \text{N} \), \( m = 36 \, \text{kg} \)

Step2: Substitute values

\( a = \frac{12}{36} \)
\( a = 0.33 \, \text{m/s}^2 \) (approx)

Answer:

1.75N (corresponding to the option with 1.75N)

Question 2