Question

Question was provided via image upload.

Explanation:

Step1: Identify shortest distance

The shortest distance is at $\frac{3}{8}$ (since the leftmost X is at $\frac{3}{8}$).

Step2: Identify longest distance

The longest distance is at $\frac{8}{8} = 1$ (rightmost X at $\frac{8}{8}$).

Step3: Sum the distances

Sum = $\frac{3}{8} + \frac{8}{8} = \frac{11}{8} = 1\frac{3}{8}$? Wait, no, wait. Wait, the labels: wait the line plot has marks at $\frac{1}{8}, \frac{2}{8}, \frac{3}{8}, \frac{4}{8}, \frac{5}{8}, \frac{6}{8}, \frac{7}{8}, \frac{8}{8}$? Wait the first mark is $\frac{1}{8}$, but the X starts at $\frac{3}{8}$? Wait the problem says "shortest distance a student ran" – looking at the line plot, the leftmost X is at $\frac{3}{8}$? Wait no, the ticks: first tick $\frac{1}{8}$, second $\frac{2}{8}$, third $\frac{3}{8}$, then $\frac{4}{8}$, $\frac{5}{8}$, $\frac{6}{8}$, $\frac{7}{8}$, $\frac{8}{8}$. The Xs: at $\frac{3}{8}$ (2 Xs), $\frac{4}{8}$ (3 Xs), $\frac{5}{8}$ (2 Xs), $\frac{6}{8}$ (3 Xs), $\frac{8}{8}$ (3 Xs)? Wait the problem says 13 students. Wait 2+3+2+3+3=13? Wait 2 (3/8) +3 (4/8)+2(5/8)+3(6/8)+3(8/8)=2+3+2+3+3=13. So shortest distance is $\frac{3}{8}$, longest is $\frac{8}{8}=1$. Wait sum is $\frac{3}{8} + 1 = \frac{3}{8} + \frac{8}{8} = \frac{11}{8} = 1\frac{3}{8}$? But the options: wait maybe I misread the ticks. Wait the first tick is $\frac{1}{8}$, but no X there. Then $\frac{2}{8}$: no X. $\frac{3}{8}$: Xs. So shortest is $\frac{3}{8}$, longest is $\frac{8}{8}=1$. Sum: $\frac{3}{8} + 1 = \frac{11}{8} = 1\frac{3}{8}$? But the options: A is 1 mile, B is $\frac{3}{8}$? No, wait maybe the longest is $\frac{8}{8}=1$, shortest is $\frac{3}{8}$? Wait no, maybe the ticks are $\frac{3}{8}$, $\frac{4}{8}$, etc. Wait the problem's line plot: the labels are $\frac{1}{8}$, $\frac{2}{8}$, $\frac{3}{8}$, $\frac{4}{8}$, $\frac{5}{8}$, $\frac{6}{8}$, $\frac{7}{8}$, $\frac{8}{8}$? Wait the user's image: the first tick is $\frac{1}{8}$, second $\frac{2}{8}$, third $\frac{3}{8}$, then $\frac{4}{8}$, $\frac{5}{8}$, $\frac{6}{8}$, $\frac{7}{8}$, $\frac{8}{8}$. The Xs: at $\frac{3}{8}$ (two Xs), $\frac{4}{8}$ (three Xs), $\frac{5}{8}$ (two Xs), $\frac{6}{8}$ (three Xs), $\frac{8}{8}$ (three Xs). Wait 2+3+2+3+3=13. So shortest distance is $\frac{3}{8}$, longest is $\frac{8}{8}=1$. Sum: $\frac{3}{8} + 1 = \frac{11}{8} = 1\frac{3}{8}$? But the options: let's check the options again. Wait maybe I misread the longest distance. Wait $\frac{8}{8}$ is 1 mile. Shortest is $\frac{3}{8}$? No, wait maybe the shortest is $\frac{3}{8}$ and longest is $\frac{8}{8}$, sum is $\frac{3}{8} + \frac{8}{8} = \frac{11}{8} = 1\frac{3}{8}$, but the options: wait the options are A. 1 mile, B. $\frac{3}{8}$ of a mile, C. $1\frac{3}{8}$ of a mile, D. $\frac{5}{8}$ of a mile? Wait the user's image: the options are A. 1 mile, B. $\frac{3}{8}$ of a mile, C. $1\frac{3}{8}$ of a mile, D. $\frac{5}{8}$ of a mile? Wait maybe the longest distance is $\frac{8}{8}=1$, shortest is $\frac{3}{8}$, sum is $1 + \frac{3}{8} = 1\frac{3}{8}$, which is option C.

Answer:

C. $1\frac{3}{8}$ of a mile