Question

how does the strength of coriolis change as an object moves from the equator towards the pole?
○ none of the above.
○ it decreases.
○ it increases.
○ it stays the same.
○ it goes to zero.

Explanation:

The Coriolis force formula is \( F = - 2m\Omega\times v \), where \( \Omega \) is the angular velocity of the Earth's rotation and \( v \) is the velocity of the object. The Coriolis parameter \( f = 2\Omega\sin\varphi \), where \( \varphi \) is the latitude. As an object moves from the equator (\( \varphi = 0^{\circ},\sin\varphi=0 \)) towards the pole (\( \varphi = 90^{\circ},\sin\varphi = 1 \)), the value of \( \sin\varphi \) increases. Since the Coriolis force is proportional to \( \sin\varphi \), the strength of the Coriolis force increases.

Answer:

It increases.