Question

1. how many total oxygen atoms are in the products of photosynthesis?
2. how many total hydrogen atoms are in the products of photosynthesis?
3. was the law of conservation of matter followed? explain with evidence from your diagram.

Explanation:

To solve these questions, we first recall the photosynthesis equation: \( 6CO_2 + 6H_2O \xrightarrow[\text{Chlorophyll}]{\text{Light}} C_6H_{12}O_6 + 6O_2 \) (products are glucose \( C_6H_{12}O_6 \) and oxygen \( O_2 \)).

Question 5: Total Oxygen Atoms in Products

Step 1: Analyze Oxygen in Glucose

Glucose formula: \( C_6H_{12}O_6 \). Number of O atoms: \( 6 \).

Step 2: Analyze Oxygen in Oxygen Gas

Oxygen gas formula: \( O_2 \), and there are 6 molecules. Each \( O_2 \) has 2 O atoms, so total O atoms: \( 6 \times 2 = 12 \).

Step 3: Sum Oxygen Atoms

Total O atoms = O in glucose + O in \( O_2 \) = \( 6 + 12 = 18 \).

Question 6: Total Hydrogen Atoms in Products

Step 1: Analyze Hydrogen in Glucose

Glucose formula: \( C_6H_{12}O_6 \). Number of H atoms: \( 12 \).

Step 2: Hydrogen in \( O_2 \)

\( O_2 \) has no H atoms, so H atoms only come from glucose. Thus, total H atoms = \( 12 \).

Question 7: Law of Conservation of Matter

The law of conservation of matter states that matter is neither created nor destroyed in a chemical reaction (atoms are conserved).

Step 1: Count Atoms in Reactants

• C: \( 6CO_2 \) has \( 6 \) C atoms.
• H: \( 6H_2O \) has \( 6 \times 2 = 12 \) H atoms.
• O: \( 6CO_2 \) ( \( 6 \times 2 = 12 \) O) + \( 6H_2O \) ( \( 6 \times 1 = 6 \) O) = \( 18 \) O atoms.

Step 2: Count Atoms in Products

• C: \( C_6H_{12}O_6 \) has \( 6 \) C atoms.
• H: \( C_6H_{12}O_6 \) has \( 12 \) H atoms.
• O: \( C_6H_{12}O_6 \) ( \( 6 \) O) + \( 6O_2 \) ( \( 12 \) O) = \( 18 \) O atoms.

Step 3: Compare Reactants and Products

The number of C, H, and O atoms is equal in reactants and products. Thus, the law of conservation of matter is followed.

Answer:

s

1. \(\boldsymbol{18}\)
2. \(\boldsymbol{12}\)
3. Yes, the law is followed. The number of C (6), H (12), and O (18) atoms is the same in reactants (\(6CO_2 + 6H_2O\)) and products (\(C_6H_{12}O_6 + 6O_2\)), so matter is conserved.