Question

how many solutions does this equation have?
3(2z + 1) = 6z + 3
no solution one solution
two solutions infinitely many solutions
submit

Explanation:

Step1: Expand the left side

Using the distributive property \(a(b + c)=ab+ac\), we expand \(3(2z + 1)\) to get \(3\times2z+3\times1 = 6z + 3\).

Step2: Compare both sides

The equation becomes \(6z + 3=6z + 3\). Subtracting \(6z\) from both sides gives \(3 = 3\), which is always true. This means any value of \(z\) will satisfy the equation.

Answer:

infinitely many solutions