QUESTION IMAGE
Question
- how many real solutions and how many non-real solutions does the equation \\(x^2+5=0\\) have? describe what implications your answer has for graphing the function \\(y=x^2+5\\).
- solve the quadratic equation using your choice of the methods we learned in this module. indicate which method you are using, and show your work.
\\4x^2 - 22 = x^2 + 5\\
Solve the first equation and determine root types
The equation has \(0\) real solutions and \(2\) non-real (complex) solutions.
Since there are no real solutions, the graph of \(y = x^2 + 5\) has no \(x\)-intercepts and does not cross or touch the \(x\)-axis.
Solve the second quadratic equation
The method used is solving by taking square roots.
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Question 2
The equation \(x^2+5=0\) has \(0\) real solutions and \(2\) non-real solutions. This implies that the graph of the function \(y=x^2+5\) has no \(x\)-intercepts and does not intersect the \(x\)-axis.
Question 3
Method: Solving by taking square roots.
The solutions are \(x = 3\) and \(x = -3\).