Question

1. how would the density of a piece of aluminum change if you had another one double its size?

Explanation:

Step1: Recall density formula

Density $
ho=\frac{m}{V}$, where $m$ is mass and $V$ is volume.

Step2: Consider the case of doubling size

If the size doubles, both mass and volume increase proportionally. Let the original mass be $m_1$ and volume be $V_1$, density $
ho_1 = \frac{m_1}{V_1}$. If the size doubles, mass becomes $m_2 = 2m_1$ and volume becomes $V_2=2V_1$. Then the new density $
ho_2=\frac{m_2}{V_2}=\frac{2m_1}{2V_1}=\frac{m_1}{V_1}$.

Answer:

The density of the aluminum would remain the same.