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homework - complete dominance inheritance pattern when a man has an all…

Question

homework - complete dominance inheritance pattern
when a man has an allele combination ww for a trait, what percentage of his gametes will have a dominant allele for that trait?
25%
50%
75%
100%

Explanation:

Step1: Gamete formation

During gamete formation, alleles segregate. For the genotype \(Ww\), the possible gametes are \(W\) and \(w\).

Step2: Calculate proportion of dominant - allele - containing gametes

There are 2 possible gametes (\(W\) and \(w\)). The number of gametes with the dominant allele (\(W\)) is 1. Using the formula \(\text{Proportion}=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\), we have \(\text{Proportion}=\frac{1}{2}\).

Step3: Convert proportion to percentage

To convert \(\frac{1}{2}\) to a percentage, we use the formula \(\text{Percentage}=\frac{1}{2}\times100\%\). So, \(\text{Percentage} = 50\%\).

Answer:

50%